Leap year

# title: Leap year
# source: https://rosettacode.org/wiki/Leap_year
# category: Rosetta Code
# difficulty: Intro
# summary: Determine whether a given year is a leap year using the Gregorian calendar rules.
# tags: popular, math, conditionals, basics
# vibe: 0.2

def leap_year?(year)
  if year % 400 == 0
    return true
  elsif year % 100 == 0
    return false
  elsif year % 4 == 0
    return true
  end
  false
end

def run
  years = [1900, 2000, 1996, 1997, 2024, 2025, 2100, 2400]
  results = []
  i = 0
  while i < years.size
    results = results.push({ year: years[i], leap: leap_year?(years[i]) })
    i = i + 1
  end
  results
end